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Surveying Property (Law of Sines)

A surveyor locating the corners of a triangular piece of property started at one corner
and walked 480ft in the direction N36°W to reach the next corner.
The surveyor turned and walked S21°W to get to the next corner of the property.
Finallythe surveyor walked in the direction N82°E to get back to the starting point.
What is the perimeter of this piece of property to the nearest foot?


can someone help me sketch out this? I tried by myself but always end up with the wrong answer.
 
Can you show us what you've tried?

sure.

when i first read the problemi sketched the triangle base on a regular law of sines one.
It says the 36 degree is on North west and I put it in that direction in the trianglesame goes with the other two.
Then did the mathand since it asked for the perimeter I added all 3 sides after
i used law of sines to find the sides. Basically I got a really big answer(the answer is 1425 ft).

firstsol.png


later found out about bearing and did this
secondsol.png
I tried to make sense of itbut the wording really confuses me
 
sure.

when i first read the problemi sketched the triangle base on a regular law of sines one.
It says the 36 degree is on North west and I put it in that direction in the trianglesame goes with the other two.
Then did the mathand since it asked for the perimeter I added all 3 sides after
i used law of sines to find the sides. Basically I got a really big answer(the answer is 1425 ft).

View attachment 23684


later found out about bearing and did this
View attachment 23685
I tried to make sense of itbut the wording really confuses me

Your latest picture is also incorrect. Each bearing is measured from the point that you are atnot from the starting point. So your sketch should look like this...

bearingsproblem.jpg
 

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